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(a^2)-17a+60=0
a = 1; b = -17; c = +60;
Δ = b2-4ac
Δ = -172-4·1·60
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-7}{2*1}=\frac{10}{2} =5 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+7}{2*1}=\frac{24}{2} =12 $
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